Question

A man observed from the top of the electric pole, the angle of depression of a point on the ground is ${60}^o$. If the distance of a point from the foot of the electric pole is $25m$, then find the height of the electric pole.

Answer 1

Let $AB$ be the pole, $C$ be the point from where the man observes the pole.

In $△ABC,\angle B={90}^{\circ }$

$\tan 60=\frac{AB}{BC}$

$=\frac{AB}{25}$

$AB=25\sqrt{3}m$

Therefore height of the pole $=25\sqrt{3}m$