Question

A man of mass 40 kg is standing on a uniform plank of mass 60 kg lying on horizontal frictionless ice. The man walks from one end to the other end of the plank . the distance walked by the man relative to ice is (given length of plank=5m)

• A. 2 m
• B. 3 m
• C. 5 m
• D. 4 m

Answer 1

The correct option is A 2 m

d = $\frac{mL}{m_1+m_2}$

$\frac{40\times 5m}{100}$

= 2m