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Question

A man of mass 40 kg is standing on a platform of 12 kg. If the man starts running at 6 m/s relative to the platform, the velocity of the platform relative to the ground is

A
3 m/s
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B
4.6 m/s
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C
2 m/s
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D
6 m/s
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Solution

The correct option is B 4.6 m/s

Mass of the platform m1=12 kg
Mass of the man m2=40 kg
Taking rightward direction as +ve,
Let velocity of platform relative to the ground be v towards left.
v1=v
Then, velocity of man relative to the ground is (6v)
v2=6v
Using momentum conservation,
0=m1v1+m2v2 (initially, both at rest)
40(6v)=12v
240=52v
v=24052
v=4.6 m/s (towards left)

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