A man of mass 50 kg falls freely from a height of 40 m into a swimming pool and just come to rest at the bottom of the pool. Assume that the average upward force on the man due to water is 1000 N. If depth of water in the pool is $d$ , then $d$ is $(g = 10 m / s^{2})$

20 m

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40 m

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10 m

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5 m

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Solution

The correct option is B 40 m
Answer is B
Potential energy of the man will be equal to work done by the upward force of water.
Therefore,
mg(h+d)= Fd
500X40=1000d-500d
d=40m

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A man of mass 50 kg falls freely from a height of 40 m into a swimming pool and just come to rest at the bottom of the pool. Assume that the average upward force on the man due to water is 1000 N. If depth of water in the pool is d, then d is (g=10 m/s2)

The correct option is B 40 mAnswer is BPotential energy of the man will be equal to work done by the upward force of water.Therefore,mg(h+d)= Fd500X40=1000d-500dd=40m

A man of mass 50 kg falls freely from a height of 40 m into a swimming pool and just come to rest at the bottom of the pool. Assume that the average upward force on the man due to water is 1000 N. If depth of water in the pool is $d$ , then $d$ is $(g = 10 m / s^{2})$

The correct option is B 40 m
Answer is B
Potential energy of the man will be equal to work done by the upward force of water.
Therefore,
mg(h+d)= Fd
500X40=1000d-500d
d=40m