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Question
A man of mass 50 kg stands on a frame of mass 30 kg. He pulls on a light rope which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equilibrium, what force must the man exert on the rope? (Take g=10 m/s2)
A man of mass 50 kg stands on a frame of mass 30 kg. He pulls on a light rope which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equilibrium, what force must the man exert on the rope? (Take g=10 m/s2)
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Solution
The correct option is A 400 N
Force exerted by man on rope transfers to it in the form of tension.
Net upwards force on the system is 2T or 2F.
Net downward force is (50+30)g = 80 g.
For equilibrium of system, 2F=80 g
or F=40 g=400 N
Force exerted by man on rope transfers to it in the form of tension.
Net upwards force on the system is 2T or 2F.
Net downward force is (50+30)g = 80 g.
For equilibrium of system, 2F=80 g
or F=40 g=400 N
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