A man of mass $60 k g$ climbs up a $20 m$ long staircase on the top of a building $10 m$ high. What is the work done by him? $(T a k e g = 10 m s^{- 2})$

12 k J

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6 k J

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3 k J

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18 k J

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Solution

The correct option is C $18 k J$
m $=$ 60 kg
Length of staircase $=$ 20 m
Height of staircase $=$ 10 m
Workdone $=$ mgh $=$ mg (length + height of stair case)
$= 60 \times 10 \times (20 + 10)$
$600 \times 30 = 18 k J$

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