A man of mass 60 kg is standing on a horizontal conveyer belt (fig). When the belt is given an acceleration of $1 m s^{- 2}$ , the man remains stationary with respect to the moving belt. If $g = 10 m s^{- 2}$ , the net force acting on the man is :

-0.6 N

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6 N

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60 N

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600 N

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Solution

The correct option is C 60 N
Mass of man =60 kg
The conveyer belt is moving with an acceleration of $1 m / s^{2}$ .
As man is stationary with respect to moving belt, so the acceleration of man will be the same as that of moving belt.
So, acceleration of man, a = $1 m / s^{2}$
Hence, the net force on man $= m a$
$= 60 \times 1 = 60 N$

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A man of mass 60 kg is standing on a horizontal conveyer belt (fig). When the belt is given an acceleration of 1ms−2, the man remains stationary with respect to the moving belt. If g=10ms−2, the net force acting on the man is :

The correct option is C 60 NMass of man =60 kgThe conveyer belt is moving with an acceleration of 1m/s2.As man is stationary with respect to moving belt, so the acceleration of man will be the same as that of moving belt.So, acceleration of man, a =1m/s2Hence, the net force on man =ma =60×1=60N

A man of mass 60 kg is standing on a horizontal conveyer belt (fig). When the belt is given an acceleration of $1 m s^{- 2}$ , the man remains stationary with respect to the moving belt. If $g = 10 m s^{- 2}$ , the net force acting on the man is :