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Question

A man of mass 60 kg is standing on a horizontal conveyor belt. When the belt is given an acceleration of 2ms−2, the man slides back on the belt with an acceleration 1m/s2, with respect to the belt. If g=10ms−2, the net force (in Newton) acting on the man will be :

A
60
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B
90
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C
30
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D
120
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Solution

The correct option is A 60
Since acceleration of belt with respect to ground is 2m/s2
and acceleration of man w.r.t belt is 1m/s2
therefore acceleration of man w.r.t ground will be
amg=abgamb
where, amg is acceleration of man w.r.t ground
abg is acceleration of belt w.r.t ground
amb is acceleration of man w.r.t belt
amg=21=1m/s2
Therefore, net force acting on man will be
Fnet=mass×amg
Fnet=60×1
Fnet=60N
option (A) is correct

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