Question

A man of mass 60 kg is standing on a platform which is oscillating up and down with frequency 2 Hz and amplitude 50 cm. A machine on the platform indicates weight of the man with respect to time, then the maximum reading of the machine will be $(g=10m/s^2)$

• A. 10 kg
• B. 532.8 kg
• C. 10³ kg
• D. 10⁴ kg

Answer 1

The correct option is B

532.8 kg

The maximum acceleration of the platform

$a_{max}={\omega }^{2}A=4{\pi }^2{f}^{2}A$

$=4\times 9.86\times 4\times 0.5=78.8m/s^2$

Maximum reading of the machine for mass will be,

$=\frac{m(g+A_{max})}{g}=\frac{60\times (10+78.8)}{10}$

$=\frac{60\times 88.8}{10}=532.8kg$