Question

A man of mass $60kg$ standing on an elevator moves down with acceleration $2m/s^2$. Find the change percentage of apparent weight of man

Answer 1

Given$,$

weight of man $=60kg$

downwards acceleration $=2m/s^2$

Now$,$ when lift moves downwards

$w_2=m\left(g-a\right)$

$=60\left(10-2\right)m/s^2$

$=480N$

Again$,$ $w_1=mg$

$\therefore w_1=60\times 10=600N$

Now$,$ change percentage of apparent weight

$=\frac{w_1-w_2}{w_1}\times 100$

$\frac{600-480}{600}\times 100=20\%$

$\therefore$ change is $20\%.$