A man of mass 72 kg is standing at the end of the diving board of mass 28 kg as shown in figure. A and B are two supports for the board. [g=10m/s2]
A
Force on support A is 2520 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Force on support B is 3870 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Force on support A is 2870 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
As man moves towards A, force on support B decreases.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are B Force on support B is 3870 N C Force on support A is 2870 N D As man moves towards A, force on support B decreases.
By torque equilibrium about B
NA×1=280×1.25+720×3.5
NA=2870 N
By balancing the forces in the vertical direction, NB=NA+280+720⇒NB=3870N As the man moves towards left, to balance torque, NA decreases. So, to balance, the force in the vertical direction, NB also decreases.