Question

A man of mass 75 kg stands in a lift. What force does the floor exert on him when the lift starts moving upwards with an acceleration of $2m/s^2$? $(g=10m/s^2)$

Answer 1

The FBD diagram as shown

Let floor exert a normal force acting on the man is N and its acceleration is $2m{s}^{-2}$

$N-750N=75\times 2N$

$\Rightarrow N=900N$