Question

A man of mass $80$ kg is riding on a trolley of mass $40$ kg which is rolling along a level surface at a speed of $2$ m/s. He jumps off the back of the trolley so that his speed relative to the ground is:

Answer 1

$\overrightarrow{v_{cart}=\overrightarrow{v_c}}=2\uparrow$

$\overrightarrow{v_m=\overrightarrow{v_{mc}}}+\overrightarrow{v_c}$

=-3$\uparrow$+2$\uparrow$

$\uparrow$

$\overrightarrow{v_m=\frac{80(-\uparrow )+40(2\uparrow )}{80+40}=0}$