The correct option is C The magnitude of relative velocity of the boat with respect to the walking man is greater than the magnitude of the relative velocity of the boat w.r.t. the stationary observer.
Given,
mass of man M=(m1)=50 kg
mass of boat m=(m2)=300 kg
With respect to the stationary observer, man moves with a velocity v=2 m/s and assume boat moves with a velocity =v1 m/s.
As we know, there is no external force on the system. Hence, the velocity of COM is zero (Vcom=0)
To determine the velocity of the boat with respect to a stationary observer on land :-
Vcom=m1v+m2v1m1+m2=0
m1v+m2v1=0
50×2+300×v1=0
v1=−13 m/s=−0.33 m/s
The negative sign implies that boat is moving in a direction opposite to that of the walking man on the boat (for a stationary observer on land)
To determine velocity of boat w.r.t walking man, we can find relative velocity as
vbm=vb−vm
where vbm= velocity of boat w.r.t walking man
vb= velocity of boat w.r.t. stationary observer =v1
vm= velocity of walking man w.r.t stationary observer =v
∴vbm=(−13)−(2)=−73 m/s
=−2.33 m/s
Hence magnitude of relative velocity of boat w.r.t the walking man is greater than the magnitude of the relative velocity of boat w.r.t the stationary observer.
Option (a) and (c) are correct.