CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Inertia

A man of mass...

Question

A man of mass m climbs a rope ladder suspended below a balloon of mass M .The balloon is stationary with respect to ground .If the man begins to climb the ladder with speed V find the speed of the balloon with respect to the ground

Open in App

Solution

Suggest Corrections

thumbs-up

16

Similar questions

Q. A man of mass

m

climbs on a rope of length

L

suspended below a balloon of mass

M

. The balloon is stationary with respect to ground. If the man begins to climb up the rope at a speed

V_{r e l}

(relative to rope). In what direction and with what speed (relative to ground) will the balloon move?

Q. A man of mass

m

climbs a rope of length

L

suspended below a balloon of mass

M

. The balloon is stationary with respect to ground. If the man begins to climb up the rope at a speed

_{r e l}

(relative to rope). Find velocity of balloon relative to the ground ?

Q. A man of mass

m

climbs a rope of length

L

suspended below a balloon of mass

M

. The balloon is stationary with respect to ground. If the man begins to climb up the rope at a speed

v_{rel}

(relative to the rope), in what direction and with what speed (relative to the ground) will the balloon move?

Q. A man of mass

m

climbs a rope of length

L

suspended below a balloon of mass

M

. The balloon is stationary with respect to ground. If the man begins to climb up the rope at a speed

_{r e l}

(relative to rope). Find velocity of balloon relative to the ground ?

Q. A rope ladder with a length

l

metres carrying a man with a mass

m

at its end is attached to the basket of a balloon with a mass

M

. The entire system is in equilibrium in the air. As the man climbs up the ladder into the balloon, the balloon descends by a height h. In this case, the potential energy of the balloon:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

First Law of Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon