A man of mass m kg is standing on a weighing machine which is kept in an elevator. Find the reading of the spring balance if the elevator is going up with an acceleration g/10.

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Solution

Given that,

Mass of body, $m$

Acceleration, $a = \frac{g}{10}$

The lift is ascending with an acceleration

According to figure

$T = m a + m g = m (\frac{g}{10} + g)$

$T = \frac{11}{10} m g$

Hence, Spring read $\frac{11}{10} m k g f$ force.

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A man of mass m kg is standing on a weighing machine which is kept in an elevator. Find the reading of the spring balance if the elevator is going up with an acceleration g/10.

Given that, Mass of body, m Acceleration, a=g10 The lift is ascending with an acceleration According to figure T=ma+mg=m(g10+g) T=1110mg Hence, Spring read 1110mkgf force.

Given that,

Mass of body, $m$

Acceleration, $a = \frac{g}{10}$

The lift is ascending with an acceleration

According to figure

$T = m a + m g = m (\frac{g}{10} + g)$

$T = \frac{11}{10} m g$

Hence, Spring read $\frac{11}{10} m k g f$ force.