A man of mass m slides down along a rope that is connected to the ceiling of an elevator with deceleration a relative to the rope. If the elevator is going upward with an acceleration a relative to the ground, then tension in the rope is
A
mg
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B
m(g+2a)
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C
m(g+a)
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D
zero
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Solution
The correct option is Bm(g+2a) Net acceleration of man w.r.t ground, =a−(−a)=2a
From the given figure we get the force equation as T−mg=m(2a) ∴T=m(g+2a)