A man of mass m slides down along a rope which is connected to the ceiling of an elevator with a deceleration a relative to the rope. If the elevator is going upward with an acceleration a relative to the ground, then tension in the rope is:
A
mg
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B
m(g+2a)
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C
m(g+a)
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D
zero
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Solution
The correct option is Bm(g+2a) The upward acceleration of man relative to ground is g′=g+a+a=g+2a Tension in the rope is T=mg′=m(g+2a)