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Standard XII

Physics

Gravtiational PE

A man of mass...

Question

A man of mass $m$ slides down along a rope which is connected to the ceiling of an elevator with a deceleration $a$ relative to the rope. If the elevator is going upward with an acceleration $a$ relative to the ground, then tension in the rope is:

m g

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m (g + 2 a)

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m (g + a)

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z e r o

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Solution

The correct option is B $m (g + 2 a)$
The upward acceleration of man relative to ground is $g^{'} = g + a + a = g + 2 a$
Tension in the rope is $T = m g^{'} = m (g + 2 a)$

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A man of mass m slides down along a rope which is connected to the ceiling of an elevator with a deceleration a relative to the rope. If the elevator is going upward with an acceleration a relative to the ground, then tension in the rope is:

The correct option is B m(g+2a)The upward acceleration of man relative to ground is g′=g+a+a=g+2aTension in the rope is T=mg′=m(g+2a)

A man of mass $m$ slides down along a rope which is connected to the ceiling of an elevator with a deceleration $a$ relative to the rope. If the elevator is going upward with an acceleration $a$ relative to the ground, then tension in the rope is:

The correct option is B $m (g + 2 a)$
The upward acceleration of man relative to ground is $g^{'} = g + a + a = g + 2 a$
Tension in the rope is $T = m g^{'} = m (g + 2 a)$