A man of mass m speeds up while running from rest to a speed v in a straight track along an inclined plane, after rising through a height h.
$W_{g r a v i t y}$ = work done by gravity on the man.
$W_{f r i c t i o n}$ = work done by gravity on the man.
$W_{m a n}$ = work done by man.
If in the previous problem, we replace the man by a block of mass m and release it from top of the inclined plane, and let it gain a speed v, then

W_{f r i c t i o n} = - m g h + \frac{1}{2} m v^{2}

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W_{g r a v i t y} = - m g h

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W_{f r i c t i o n} = 0

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W_{f r i c t i o n} = - μ g x

, where x is the horizontal distance covered and

μ

is the coefficient of friction between the block and the ground.

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Solution

The correct options are
A $W_{f r i c t i o n} = - m g h + \frac{1}{2} m v^{2}$
B $W_{f r i c t i o n} = 0$
C $W_{g r a v i t y} = - m g h$
A. $W_{f r i c t i o n} = - m g h + \frac{1}{2} m v^{2}$
B. $W_{g r a v i t y} = - m g h$
C. $W_{f r i c t i o n} = 0$
Hence, the answers are multiple.

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