A man of mass m speeds up while running from rest to a speed v in a straight track along an inclined plane, after rising through a height h.
$W_{g r a v i t y}$ = work done by gravity on the man.
$W_{f r i c t i o n}$ = work done by gravity on the man.
$W_{m a n}$ = work done by man.
Which of the following options is correct regarding the various work done?

W_{g r a v i t y}

= -mgh

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W_{f r i c t i o n}

> 0

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W_{m a n} = m g h + \frac{1}{2} m v^{2}

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W_{f r i c t i o n}

= 0

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Solution

The correct options are
A $W_{g r a v i t y}$ = -mgh
C $W_{m a n} = m g h + \frac{1}{2} m v^{2}$
D $W_{f r i c t i o n}$ = 0
A. $W_{g r a v i t y} = - m g h$
C. $W_{m a n} = m g h + \frac{1}{2} m v^{2}$
D. $W_{f r i c t i o n} = 0$
Hence, this question has multiple solutions.

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