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Question

A man of mass 'm' stands on a weighing machine in a lift

List - I List-II
(a) Lift moves up with uniform acceleration a
(d) mg
(b) Lift moves down with uniform acceleration a(e) m(g+a)
(c) Lift moves down with uniform velocity(f) m(g-a)

A
ae,bf,cd,
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B
ad,bf,ce,
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C
ad,be,cf,
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D
af,bd,ce,
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Solution

The correct option is A ae,bf,cd,
When the lift moves UP with uniform acceleration a Pseudo force on the man is ma downward.
Net downward force is mg+ma. Hence, e

When the lift moves down with uniform acceleration a Pseudo force on the man is ma upward.
Net downward force is mg+ma. Hence, f

When the lift moves down with uniform velocity, only force acting is gravity.

Hence net force on man is mg. Hence, d

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