A man of mass m walks from end A to the other end B of a boat of mass M and length l. The coefficient of friction between the man and the boat is μ and neglect any resistive force between the boat and the water.
A
If the man runs at his maximum acceleration, the acceleration of the boat is (m/M)g.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
The maximum time take by the men to reach the other end of the boat is √2Ml(M+m)μg.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
If the man runs at his maximum acceleration, the acceleration of the boat is mm+Mμg.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
The minimum time take by the men to reach the other end of the boat is √2ml(M+m)μg.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are A If the man runs at his maximum acceleration, the acceleration of the boat is (m/M)g. B The maximum time take by the men to reach the other end of the boat is √2Ml(M+m)μg. Maximum acceleration of the man =μmg/m=μg Maximum acceleration of the boat =μmg/M Maximum relative acceleration: arel=μg+μgmM=(M+m)Mμg Srel=12arelt2⇒t=√2lMμg(M+m)