A man of weight mg is moving upwards in a rocket with acceleration $4$ g. His apparent weight in side the rocket will be?

Zero

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Solution

The correct option is B $4$ mg
Given weight of the man =mg.
Thus mass of the man = m(as the quantity of mass does not changes with respect to location)
Also we know Force= mass $\times$ acceleration -----(1)
Here acceleration =4g.
So equation 1 can be written as =m $\times$ 4g=4mg

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A man of weight mg is moving upwards in a rocket with acceleration 4g. His apparent weight in side the rocket will be?

The correct option is B 4 mgGiven weight of the man =mg.Thus mass of the man = m(as the quantity of mass does not changes with respect to location)Also we know Force= mass×acceleration -----(1)Here acceleration =4g.So equation 1 can be written as =m×4g=4mg

A man of weight mg is moving upwards in a rocket with acceleration $4$ g. His apparent weight in side the rocket will be?

The correct option is B $4$ mg
Given weight of the man =mg.
Thus mass of the man = m(as the quantity of mass does not changes with respect to location)
Also we know Force= mass $\times$ acceleration -----(1)
Here acceleration =4g.
So equation 1 can be written as =m $\times$ 4g=4mg