A man packed 10 boxes of oranges with each box containing 8 oranges. If 10 of these oranges were rotten and removed, what will be the number of oranges in each box now?

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Solution

The correct option is C 7
Initially,

Total number of boxes = 10
Number of oranges in each box = 8
Total number of oranges = 8 $\times$ 10
= 80 oranges

Number of oranges rotten
= 10
Now total number of oranges remaining
= 80 - 10
= 70

We can write
70 ÷ 10 = ?
as we know
70 = 7 $\times$ 10
70 ÷ 10 = 7
It means each box will now have 7 oranges.

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