A man purchased LCD TV for $R s 32, 500$ . He paid $R s 200$ initially and increasing the payments by $R s . 150$ every month. How many months didi he takes to complete payment?

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Solution

$S_{n} = 32, 500$
$a = R s 200$
$d = R s 150$
$n = ?$
as Sum of A.P $\Rightarrow S_{n} = \frac{n}{2} [2 a + (n - 1) d]$
$32, 500 = \frac{n}{2} [2 (200) + (n - 1) 150]$
$32, 500 = \frac{n}{2} \times 5 [250 + 150 n]$
$0 = 150 n^{2} + 250 n - (32500 \times 2)$
$\Rightarrow 50 (n - 20) (3 n + 65) = 0$
$n \neq \frac{- 65}{3}, 30$
Months $r q^{d} \Rightarrow$ $20$

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A man purchased LCD TV for Rs32,500. He paid Rs200 initially and increasing the payments by Rs.150 every month. How many months didi he takes to complete payment?

Sn=32,500a=Rs200d=Rs150n=?as Sum of A.P ⇒Sn=n2[2a+(n−1)d]32,500=n2[2(200)+(n−1)150]32,500=n2×5[250+150n]0=150n2+250n−(32500×2)⇒50(n−20)(3n+65)=0n≠−653,30 Months rqd⇒ 20

A man purchased LCD TV for $R s 32, 500$ . He paid $R s 200$ initially and increasing the payments by $R s . 150$ every month. How many months didi he takes to complete payment?