A man pushes a block of 30kg along a level floor at a constant speed with a force directed at 45o below the horizontal. If the coefficient of friction is 0.20, then match the following.
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Solution
{m=30kg,θ=45degree,μ=θ.20} given
Work done by all the forces:
Work done by force of gravity = 0(θ=90degree) force of gravity is perpendicular to displacement.
Work done by man on the block =F.cosθ.S =0 because block moves with constant speed so (F=0)
Force=0
(Net force on the block=0) because block moves with constant speed as given in the question.