A man runs across the roof top of a tall building and jumps horizontally with the hope of landing on the roof of the next building which is of a lower height than the first. If his speed is 9 m/s, the horizontal distance between the two buildings is 10 m and the height difference is 9 m. Will he be able to land on the next building? (g = 10 m/s²).

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Solution

$Time taken to reach 9 m vertically down : t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 9}{10}} = \sqrt{\frac{18}{10}} Horizontal distance travelled when it reaches 9 m vertically down : X = ut = 9 \times \sqrt{\frac{18}{10}} = 12.1 m As the horizontal distance travelled by the man is larger when compared to the horizontal distance between the buildings, it can be concluded that the man can be able to land on the next building safely .$

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