A man saved Rs. 16,500 in 10 years. Every year, he saves ₹100 more than what he saved the year before. How much money did he save in the first year?

1000

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1100

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1200

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1300

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None of these

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Solution

The correct option is C 1200
$d = 100 \frac{n}{2} \times (2 a + (n - 1) d) = 16500 \frac{10}{2} \times (2 a + (9) 100) = 16500 10 a + 4500 = 16500 a = 1200$

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A man saved Rs. 16,500 in 10 years. Every year, he saves ₹100 more than what he saved the year before. How much money did he save in the first year?

The correct option is C 1200d=100n2×(2a+(n−1)d)=16500102×(2a+(9)100)=1650010a+4500=16500a=1200

The correct option is C 1200
$d = 100 \frac{n}{2} \times (2 a + (n - 1) d) = 16500 \frac{10}{2} \times (2 a + (9) 100) = 16500 10 a + 4500 = 16500 a = 1200$