A man sells a handset for Rs5600 and incurs a loss of 20%. He sells a second handset at a profit of 50%. If on the whole transaction, he neither gains nor less, find the cost price of the second handset.
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Solution
Let the cost price of first handset be 'x' then
SP= Rs 56.00
loss = 20%
loss= CP−SPCP×100
0.20=x−5600x
5600x=1−0.20=0.80
x=5600000.80=7,000 Rs
Now loss in this deal = 7,000- 5600= 1400 Rs
if he sells second handset in profit equal to loss in first handset then