wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man sells a handset for Rs5600 and incurs a loss of 20%. He sells a second handset at a profit of 50%. If on the whole transaction, he neither gains nor less, find the cost price of the second handset.

Open in App
Solution

Let the cost price of first handset be 'x' then
SP= Rs 56.00
loss = 20%
loss= CPSPCP×100
0.20=x5600x
5600x=10.20=0.80
x=5600000.80=7,000 Rs
Now loss in this deal = 7,000- 5600= 1400 Rs
if he sells second handset in profit equal to loss in first handset then
profit % = SPCPCP×100
50=1400x×100
x=1400×10050=2800Rs

1212852_1365672_ans_8815f84f427d4d4e8722d3ec92eb7014.JPG

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Finding Discounts
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon