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Question

A man sells a handset for Rs5600 and incurs a loss of 20%. He sells a second handset at a profit of 50%. If on the whole transaction, he neither gains nor less, find the cost price of the second handset.

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Solution

Let the cost price of first handset be 'x' then
SP= Rs 56.00
loss = 20%
loss= CPSPCP×100
0.20=x5600x
5600x=10.20=0.80
x=5600000.80=7,000 Rs
Now loss in this deal = 7,000- 5600= 1400 Rs
if he sells second handset in profit equal to loss in first handset then
profit % = SPCPCP×100
50=1400x×100
x=1400×10050=2800Rs

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