Question

A man sells three articles. First article for $Rs24,000$ at $20\%$ profit, second article for $Rs18,900$ at $125\%$ profit and the third for $Rs14,850.$ If on the whole, he gains $3\frac{1}{8}\%,$ find the cost price of the third article.

Answer 1

Let the C.P of third article be x

C.P of first article = $\frac{24000\times 100}{120}$ = Rs. $20000$

C.P of second article = $\frac{18900\times 100}{225}$ = Rs. $8400$

Given profit % = 3.125

Profit % = $\left(\frac{Profit}{C.P}\right)$

$\therefore \frac{3.125}{100}=\frac{S.P-C.P}{C.P}$

$3.125$ C.P = $100$ S.P- $100$ C.P

$103.125$ C.P = $100$ S.P

$103.125$ $\times (28400+x)=100\times \left(57750\right)$

$2928750$ + $103.125x$ = $5775000$

$103.125x=5775000$- $2928750$

$103.125x=2846250$

$x=\frac{2846250}{103.125}$

$x=27600$

$\therefore$ the cost price of the third article is Rs.$27600$

Ans = Rs.$27600$