Question

A man sets his watch by the noon whistle of a factory at a distance of $1.5km.$ Then the number of seconds his watch slower than the clock of the factory (velocity of sound $=332m/s$) is

• A. $4.52sec$
• B. $5.35sec$
• C. $2.18sec$
• D. $3.76sec$

Answer 1

The correct option is A $4.52sec$

time taken for the whistle to reach the person is $\frac{d}{v}$
$=\frac{1.5\times 1000}{332}=4.52sec$
$\therefore$ delay of his clock is $4.52s$