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Standard XII

Physics

Tension in a String

A man sits on...

Question

A man sits on a chair supported by a rope passing over a frictionless fixed pulley. The man who weights $1000 N$ exerts a force of $450 N$ on the chair downwards while pulling on the rope. If the chair weighs $250 N$ and $g$ is $10 m / s^{2}$ , then the acceleration of the chair _____.

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Solution

$\frac{1250}{10} \times a = 1250 - 450 \Rightarrow a = \frac{800 \times 10}{1250} = \frac{8000}{1250} = 6.4 m / s^{2}$

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Similar questions

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A man sits on a chair supported by a rope passing over a frictionless fixed pulley. The man who weights 1000N exerts a force of 450N on the chair downwards while pulling on the rope. If the chair weighs 250N and g is 10m/s2, then the acceleration of the chair _____.

125010×a=1250−450⇒a=800×101250=80001250=6.4m/s2

A man sits on a chair supported by a rope passing over a frictionless fixed pulley. The man who weights $1000 N$ exerts a force of $450 N$ on the chair downwards while pulling on the rope. If the chair weighs $250 N$ and $g$ is $10 m / s^{2}$ , then the acceleration of the chair _____.

$\frac{1250}{10} \times a = 1250 - 450 \Rightarrow a = \frac{800 \times 10}{1250} = \frac{8000}{1250} = 6.4 m / s^{2}$