Question

A man slides down a light rope the breaking strength of which is $\beta$ times his weight $(\beta <1)$. The maximum acceleration of man so that the rope just breaks is:

• A. $\beta g$
• B. $(1-\beta )g$
• C. $\frac{g}{1+\beta }$
• D. $\frac{g}{2-\beta }$

Answer 1

Answer: (B)

$(1-\beta )g$

By Newton's second law ,
$ma=mg-\beta mg$
$a=(1-\beta )g$