Question

A man slides down a snow covered hill along a curved path and falls $20$m below his initial position. The velocity in m/sec with which he finally strikes the ground is? $(g=10m/se{c}^2)$.

• A. $20$
• B. $400$
• C. $200$
• D. $40$

Answer 1

Answer: (A)

$20$

The equation of motion is

$v^2=u^2+2gh$

$v^2=0+2gh$

$v^2=\sqrt{2gh}$

$v=\sqrt{2\times 10\times 20}$

$v=20\frac{m}{s}$