Question

A man slides down a snow covered hill, along a curved path and falls $20m$ below his initial position. The velocity in $m/sec$, with which he finally strikes the ground is ? $(g=10m/se{c}^2)$

• A. $20$
• B. $400$
• C. $200$
• D. $40$

Answer 1

The correct option is A $20$

Given,

$h=20m$

$u=0m/s$

$g=10m/s^2$

From 3rd equation of motion,

$2gh=v^2-u^2$

$2gh=v^2-0^2=v^2$

$v=\sqrt{2gh}$

$v=\sqrt{2\times 10\times 20}=20m/s$

The correct option is A.