Question

A man slides freely down a frictionless inclined plane while his bag falls down vertically from the same height. The final speeds of the man $\left(v_M\right)$ and the bag $\left(v_B\right)$ should be such that:

• A. $v_M<v_B$
• B. $v_M=v_B$
• C. $Theydependonthemasses$
• D. $v_M>v_B$

Answer 1

The correct option is B $v_M=v_B$

By conservation of energy

$\frac{1}{2}m{v}^2=mgh$

$v=\sqrt{2gh}$

v does not depend on masses

So $v_m=v_b$