A man sold his bicycle for 405 losing one-tenth of its cost price. Find : (i) its cost price; (ii) the loss percent.
(i) Let C.P. of the bicycle = Rs. x
∴ Loss = Rs. x10
S.P = C.P - Loss
= x−x10
But, we are given S.P. = Rs.405
∴x−x10=405
⇒10x−x10 = 405
⇒9x10=405⇒x=405×109
⇒x=40509⇒x=450
∴ C.P. = Rs. 450
(ii) Loss = x10
= 45010
... (Substituting the value of x)
Loss % = LossC.P.×100
= 45450×100=4500450 = 10%