Question

A man sold his bicycle for 405 losing one-tenth of its cost price. Find : (i) its cost price; (ii) the loss percent.

Answer 1

(i) Let C.P. of the bicycle = Rs. x
$\therefore$ Loss = Rs. $\frac{x}{10}$
S.P = C.P - Loss
= $x-\frac{x}{10}$
But, we are given S.P. = Rs.405
$\therefore x-\frac{x}{10}=405$
$\Rightarrow \frac{10x-x}{10}$ = 405
$\Rightarrow \frac{9x}{10}=405\Rightarrow x=405\times \frac{10}{9}$
$\Rightarrow x=\frac{4050}{9}\Rightarrow x=450$
$\therefore$ C.P. = Rs. 450
(ii) Loss = $\frac{x}{10}$
= $\frac{450}{10}$
... (Substituting the value of x)
Loss % = $\frac{Loss}{C.P.}\times 100$
= $\frac{45}{450}\times 100=\frac{4500}{450}$ = 10%