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Question
A man spends 6.4 kJ energy in displacing a body by 64 m in the direction in which he applies force,in 2.5 s.Calculate :(i) the force applied, and (ii) the power spent(in H.P.) by the man.
A man spends 6.4 kJ energy in displacing a body by 64 m in the direction in which he applies force,in 2.5 s.Calculate :(i) the force applied, and (ii) the power spent(in H.P.) by the man.
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Solution
Work done by man = 6.4kJ Distance moved, S = 64m
(i) Work done by the man= Force x distance moved in direction of force Work,
W = F × S
6.4× 1000 =F × 64
(ii) the power spent(in H.P.) by the man.
1 HP=746 W
2560/746=3.4316HP
Work done by man = 6.4kJ Distance moved, S = 64m
(i) Work done by the man= Force x distance moved in direction of force Work,
W = F × S
6.4× 1000 =F × 64
(ii) the power spent(in H.P.) by the man.
1 HP=746 W
2560/746=3.4316HP
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