A man spends $6.4 k J$ energy in displacing a body by $64 m$ in the direction in which he applies force, in $2.5 s$ .
Calculate the force applied.

1 N

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10 N

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0.1 N

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100 N

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Solution

The correct option is D $100 N$
We know that $W o r k = F o r c e \times d i s p l a c e m e n t$ .
Here, given $E n e r g y = 6.4 k J = 6400 J$
$⟹ W o r k = 64000 J$ and $d i s p l a c e m e n t = 64 m$ .

$F o r c e = \frac{W o r k}{d i s p l a c e m e n t} = 6400 / 64 = 100 N$ .

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A man spends 6.4 kJ energy in displacing a body by 64 m in the direction in which he applies force, in 2.5 s. Calculate the force applied.

The correct option is D 100NWe know that Work=Force×displacement.Here, given Energy=6.4 kJ=6400 J ⟹Work=64000J and displacement=64 m.Force=Workdisplacement=6400/64=100N.

A man spends $6.4 k J$ energy in displacing a body by $64 m$ in the direction in which he applies force, in $2.5 s$ .
Calculate the force applied.

The correct option is D $100 N$
We know that $W o r k = F o r c e \times d i s p l a c e m e n t$ .
Here, given $E n e r g y = 6.4 k J = 6400 J$
$⟹ W o r k = 64000 J$ and $d i s p l a c e m e n t = 64 m$ .

$F o r c e = \frac{W o r k}{d i s p l a c e m e n t} = 6400 / 64 = 100 N$ .