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Question

A man spends 6.4kJ energy in displacing a body by 64m in the direction in which he applies force in 2.5s.Calculate :

1-the force applied

2-the power spent(in H.P.

) by the man

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Solution

Work done by man = 6.4kJ
Distance moved, S = 64m
(i) Work done by the man= Force x distance moved in direction
of force Work, W = F × S
6.4× 10^3
​​​=F × 64
Therefore
F= 64*10^3/64 =100N

Power spend =Power = Work done/Time = 6400/2.5 = 2560 watt
1 HP =746 w
Therfore 2560 watt
=2560/746=3.431 HP

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