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Standard IX

Physics

Second Law of Motion

A man standin...

Question

A man standing at a distance of 6m from a building 21.3 m high observes a kid slipping from the top floor. With what speed should he run to catch the kid at a height of 2 m from the ground? (Assume speed of the person to be uniform; $g = 10 m s^{- 2}$

1 m s^{- 1}

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2 m s^{- 1}

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1.5 m s^{- 1}

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3 m s^{- 1}

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Solution

The correct option is D $3 m s^{- 1}$
The kid will fall (21.3 - 2) =19.3m
Now, $h = (1 / 2) g t^{2}$ From here we get t = 2 sec (close to)
If u = speed of the man, then u x 2 = 6
Or u = 3 m/s

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A man standing at a distance of 6m from a building 21.3 m high observes a kid slipping from the top floor. With what speed should he run to catch the kid at a height of 2 m from the ground? (Assume speed of the person to be uniform; g=10ms−2

The correct option is D 3ms−1The kid will fall (21.3 - 2) =19.3mNow, h=(1/2)gt2 From here we get t = 2 sec (close to)If u = speed of the man, then u x 2 = 6 Or u = 3 m/s

A man standing at a distance of 6m from a building 21.3 m high observes a kid slipping from the top floor. With what speed should he run to catch the kid at a height of 2 m from the ground? (Assume speed of the person to be uniform; $g = 10 m s^{- 2}$

The correct option is D $3 m s^{- 1}$
The kid will fall (21.3 - 2) =19.3m
Now, $h = (1 / 2) g t^{2}$ From here we get t = 2 sec (close to)
If u = speed of the man, then u x 2 = 6
Or u = 3 m/s