A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340 ms−1, The distance between the cliffs is
340 m
Let the person be a distance of ‘x’m from cliff 1 and at a distance of ‘y’m from cliff 2.
The sound travels a distance of 2x in 1 second and produces one
Distance = velocity × time
2x=340×1⇒x=170m
The sound travels a distance ‘2y’ in 1 second,
⇒ y = 170m
∴ Distance between the cliffs = 170 + 170 = 340m