A man standing between two cliffs produces a sound and hears two successive echoes at intervals of 3s and 4s respectively. Calculate the distance between the two cliffs.
The speed of sound in the air is $330 m s^{- 1}$

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Solution

We know, $V = \frac{2 d}{t}$
or $2 d = V \times t$
Lets distance of man from nearer diff $= d_{1}$ and from farther diff $= d_{2}$
$d_{1} = \frac{330 \times 3}{2}$ and $d_{2} = \frac{330 \times 4}{2}$
$d_{1} = 495 m$ and $d_{2} = 660 m$
Distance between the two cliffs $= 495 + 660$
$= 1155 m$

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A man standing between two cliffs produces a sound and hears two successive echoes at intervals of 3s and 4s respectively. Calculate the distance between the two cliffs.The speed of sound in the air is 330ms−1

We know, V=2dtor 2d=V×tLets distance of man from nearer diff=d1 and from farther diff=d2d1=330×32 and d2=330×42d1=495m and d2=660mDistance between the two cliffs =495+660=1155m

A man standing between two cliffs produces a sound and hears two successive echoes at intervals of 3s and 4s respectively. Calculate the distance between the two cliffs.
The speed of sound in the air is $330 m s^{- 1}$

We know, $V = \frac{2 d}{t}$
or $2 d = V \times t$
Lets distance of man from nearer diff $= d_{1}$ and from farther diff $= d_{2}$
$d_{1} = \frac{330 \times 3}{2}$ and $d_{2} = \frac{330 \times 4}{2}$
$d_{1} = 495 m$ and $d_{2} = 660 m$
Distance between the two cliffs $= 495 + 660$
$= 1155 m$