A man standing in a valley between two parallel mountains fires a gun and hears echo at an interval of 2 s and 3.5s. What is
a) the distance between two mountains?
b) the location of the man with respect to the mountain?

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Solution

Speed of sound is taken as 340 m/sec
From the diagram:
Distance traveled by the wave to reach the mountain in 2 sec will have time taken to travel "2x" distance
$340 = \frac{2 x}{2}$
x=340 m
Now for the mountain 2 distance to be traveled:
$340 = \frac{2 (d - x)}{3.5}$
d-x =595 m
and d = 935 m

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A man standing in a valley between two parallel mountains fires a gun and hears echo at an interval of 2 s and 3.5s. What is a) the distance between two mountains? b) the location of the man with respect to the mountain?

Speed of sound is taken as 340 m/sec From the diagram: Distance traveled by the wave to reach the mountain in 2 sec will have time taken to travel "2x" distance 340=2x2 x=340 m Now for the mountain 2 distance to be traveled: 340=2(d−x)3.5 d-x =595 m and d = 935 m

A man standing in a valley between two parallel mountains fires a gun and hears echo at an interval of 2 s and 3.5s. What is
a) the distance between two mountains?
b) the location of the man with respect to the mountain?

Speed of sound is taken as 340 m/sec
From the diagram:
Distance traveled by the wave to reach the mountain in 2 sec will have time taken to travel "2x" distance
$340 = \frac{2 x}{2}$
x=340 m
Now for the mountain 2 distance to be traveled:
$340 = \frac{2 (d - x)}{3.5}$
d-x =595 m
and d = 935 m