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Question

A man standing in front of a mountain at a certain distance beats a drum at regular intervals. The drumming rate is gradually increased and he finds that the echo is not heard distinctly when the rate becomes 40 per minute. He then moves nearer to the mountain by 90 m and finds the echo is again not heard when the drumming rate becomes 60 per minute.
(a) The distance between the mountain and the initial position of the man and

(b) The velocity of sound are:

A
360m,270m/s
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B
270m,360m/s
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C
72m,360m/s
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D
150m,360m/s
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Solution

The correct option is B 270m,360m/s
Suppose the velocity of sound is V and the distance between the mountain and the initial position of the man is d.
First the drum beat was 40/minute.
So, in a minute the distance traveled by sound is: 2d×40=V×60.
Using same logic in second case:
2(dx)×60=V×60. [where =x=90m]
Solving these two equation, we can get:
d=270 m & V=360 m/s

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