A man standing on a level plain observes the elevation of the top of a pole of height h to be π/12. He then walks a distance xm towards the pole and finds that the elevation is now π/6. If h=33m then x2 is equal to
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Solution
Clearly ∠PAQ=∠APQ ⇒AQ=x (sides opposite to equal angles are equal) Now in △ABQ sin300=hAQ ⇒x=66m So, x2=4356m2