A man standing on a platform hears the sound of frequency 605 Hz coming from 550 Hz train whistle moving towards the platform. If the velocity of sound is 330 m/s. What is the speed of train?

30 m/s

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35 m/s

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40 m/s

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45 m/s

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Solution

The correct option is A 30 m/s
Apparent Frequency is given by:
$n^{'} = n (\frac{v + v_{0}}{v - v_{s}})$
$605 = 550 (\frac{330 + 0}{330 - v_{s}})$
$v_{s} = 30 m / s$

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