A man standing on the roof of a house of height h throws one particle vertically downwards and another particle horizontally with the same velocity u. The ratio of their velocities when they reach the earth’s surface will be
A
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B
1 : 2
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C
1 : 1
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D
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Solution
The correct option is C 1 : 1
For first particle: v2=u2+2gh⇒v=√u2+2gh For second particle: v=√v2x+v2y=√u2+(√2gh)2=√u2+2gh So the ratio of velocities will be 1 : 1.