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Question

A man standing on the roof of a house of height h throws one particle vertically downwards and another particle horizontally with the same velocity u. The ratio of their velocities when they reach the earth’s surface will be

A
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B
1 : 2
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C
1 : 1
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D
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Solution

The correct option is C 1 : 1

For first particle: v2=u2+2ghv=u2+2gh
For second particle: v=v2x+v2y=u2+(2gh)2=u2+2gh
So the ratio of velocities will be 1 : 1.

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