A man stands at a distance of 112 m from a vertical wall. On blowing a whistle, he hears the echo 0.7 sec. What will be the speed of sound in air?

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Solution

Here, the distance traveled by the sound in 0.7 sec is $S = 2 \times 112 = 224 m$
Using, $S = v t$ , $v = S / t = 224 / 0.7 = 320 m / s$

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A man stands at a distance of 112 m from a vertical wall. On blowing a whistle, he hears the echo 0.7 sec. What will be the speed of sound in air?

Here, the distance traveled by the sound in 0.7 sec is S=2×112=224mUsing, S=vt, v=S/t=224/0.7=320m/s

Here, the distance traveled by the sound in 0.7 sec is $S = 2 \times 112 = 224 m$
Using, $S = v t$ , $v = S / t = 224 / 0.7 = 320 m / s$