A man stands at a distance of $225 m$ from a cliff. He fires a gun and heard the echo after $1.5 s e c$ . What will be the velocity of the sound?

{300 m s}^{- 1}

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{340 m s}^{- 1}

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{320 m s}^{- 1}

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{335 m s}^{- 1}

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Solution

The correct option is A ${300 m s}^{- 1}$
The echo is the sound reflection from a surface. Thus, total distance be covered by sound is $d = 2 \times 225 = 450 m$ .
Using , $S = v t$ , we get $v = d / t = 450 / 1.5 = 300 m / s$

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A man stands at a distance of 225m from a cliff. He fires a gun and heard the echo after 1.5sec. What will be the velocity of the sound?

The correct option is A 300ms−1The echo is the sound reflection from a surface. Thus, total distance be covered by sound is d=2×225=450m.Using , S=vt, we get v=d/t=450/1.5=300m/s

A man stands at a distance of $225 m$ from a cliff. He fires a gun and heard the echo after $1.5 s e c$ . What will be the velocity of the sound?

The correct option is A ${300 m s}^{- 1}$
The echo is the sound reflection from a surface. Thus, total distance be covered by sound is $d = 2 \times 225 = 450 m$ .
Using , $S = v t$ , we get $v = d / t = 450 / 1.5 = 300 m / s$